Answer :
Final answer:
The margin of error for the mean mass of the cheetahs in the park is calculated by subtracting the smallest value in the range from the largest, and dividing by 2. So in this case, it's (182 lbs - 120 lbs) / 2 = 31 lbs.
Explanation:
The question is asking for the value of the margin of error for the mean mass of the cheetahs in the park. The margin of error is essentially the range in which the true value lies, it's the difference between the upper limit and the lower limit of data range divided by 2.
In this case, the range is the difference between the maximum mean value (182 lbs) and the minimum mean value (120 lbs). Hence, the range would be 182 lbs - 120 lbs which equals to 62 lbs. The margin of error is half of this range, so it would be 62 lbs divided by 2, resulting in a margin of error of 31 lbs.
To find the margin of error, we need to first subtract the lower limit from the upper limit:
Upper limit - Lower limit = 182 - 120 = 62 lbs
Next, we divide the difference by 2 to find the margin of error:
Margin of error = (Upper limit - Lower limit) / 2 = 62 / 2 = 31 lbs
Therefore, the value of the margin of error for the mean mass of the cheetahs in the park is 31 lbs.
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