Answer :
Final answer:
To find out how many grams 35 meq of Mn2+ is, we use the molar mass of Mn and convert milliequivalents to grams, resulting in 0.96075 grams, which is also 960.75 milligrams.
Explanation:
To calculate how many grams 35 meq (milliequivalents) of Mn2+ is, we need the molar mass of manganese (Mn). We use the molar mass of manganese, which is approximately 54.9 g/mol, as given in the solution information. First, convert milliequivalents to moles, and then to grams:
- Since 1 equivalent of a divalent cation like Mn2+ is equal to its molar mass divided by its valence (which is 2), 1 meq of Mn2+ is equal to 54.9 g/mol divided by 2, which is 27.45 g/equiv.
- Therefore, 35 meq of Mn2+ is equal to 35
× (27.45 g/1000 meq) = 0.96075 grams. - Finally, to convert grams to milligrams, multiply by 1000. So, 0.96075 grams is equal to 960.75 milligrams.
Thus, 35 meq of Mn2+ is 0.96075 grams or 960.75 milligrams.
