Answer :
The length of the rectangle is 45 m, and the width is 15 m.
Let's denote the length of the rectangle as "L" and the width as "W". According to the given information, we can set up two equations based on the given conditions:
1. W = (1/3)L (The width is one-third of the length)
2. Perimeter = 2L + 2W = 120 m
Substitute the value of "W" from the first equation into the second equation:
2L + 2(1/3)L = 120
2L + 2L/3 = 120
6L + 2L = 360
8L = 360
L = 45
Now that we have found the length, we can substitute it back into the first equation to find the width:
W = (1/3)L = (1/3)(45) = 15
Therefore, the length of the rectangle is 45 m, and the width is 15 m, satisfying the conditions given in the problem.
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