A projectile is shot from a cannon at a 40° angle relative to the ground. If the projectile started with a vertical speed of 35.9 m/s, what range did the object move, assuming the projectile comes back down to the ground?

Please make a drawing to help understand better. Thank you.

The range of the projectile is the horizontal distance it travels before hitting the ground. To calculate the range, we can use the formula Range = (Initial velocity^2 * sin(2 * launch angle)) / acceleration due to gravity. For the given values of an initial velocity of 35.9 m/s and a launch angle of 40 degrees, the range can be calculated using this formula.

Explanation:

To calculate the range of the projectile, we can use the following formula:

Range = (Initial velocity^2 * sin(2 * launch angle)) / acceleration due to gravity

Given that the initial velocity is 35.9 m/s and the launch angle is 40 degrees, we can substitute these values into the formula:

Range = (35.9^2 * sin(2 * 40)) / 9.8

Calculating this expression gives us the range of the projectile.

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A projectile is shot from a cannon at a 40° angle relative to the ground. If the projectile started with a vertical speed of 35.9 m/s, what range did the object move, assuming the projectile comes back down to the ground? Please make a drawing to help understand better. Thank you.

Answer :

Final answer:

Explanation:

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A projectile is shot from a cannon at a 40° angle relative to the ground. If the projectile started with a vertical speed of 35.9 m/s, what range did the object move, assuming the projectile comes back down to the ground?

Please make a drawing to help understand better. Thank you.