Answer :
The frequency of the photon with energy 1.57 x 10⁷ J is found to be 2.3 x 10²⁸ Hertz.
The energy and the frequency of the photon are related as,
E = hν
Where, E is energy which is given to be 1.57 x 10⁷ J, h is the plank's constant that has the value 6.62607015 × 10⁻³⁴ m² kg/s, ν is the frequency of the light.
Now, putting all the values at the corresponding places,
1.57 x 10⁷ = 6.62607015 × 10⁻³⁴(ν)
v = 1.57 x 10⁷/6.62607015 × 10⁻³⁴
v = 2.3 x 10²⁸ Hertz.
So, the frequency of the photon is 2.3 x 10²⁸ Hertz.
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The frequency of a photon with an energy of 1.57 x 10⁻¹³ J is 2.37 x 10²⁰ Hz, calculated using Planck's constant and the energy-frequency relationship.
To find the frequency of a photon when given its energy, we can use the formula E = hf, where E is the energy of the photon in joules, h is Planck's constant, and f is the frequency in hertz. Planck's constant (h) is approximately 6.626 x 10⁻³⁴ J⋅s.
First, rearrange the formula to solve for frequency: f = E / h. Now, substitute the given values.
The photon has an energy E of 1.57 x 10⁻¹³ J. Using Planck's constant, the calculation for frequency is: f = (1.57 x 10⁻¹³ J) / (6.626 x 10⁻³⁴ J⋅s) = 2.37 x 10²⁰ Hz. Therefore, the frequency of the photon is 2.37 x 10²⁰ Hz.
