High School

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------------------------------------------------ The inequality [tex]$6-\frac{2}{3}x < x-9$[/tex] is equivalent to:

A. [tex]$x > 9$[/tex]

B. [tex]$x < 9$[/tex]

C. [tex]$x > -\frac{3}{5}$[/tex]

D. [tex]$x < -\frac{3}{5}$[/tex]

Answer :

To solve the inequality [tex]\(6 - \frac{2}{3}x < x - 9\)[/tex], we follow these steps:

1. Eliminate Fractions:
Start by clearing the fraction. You can do this by multiplying every term in the inequality by 3 to eliminate the denominator.

[tex]\[
3 \cdot 6 - 3 \cdot \frac{2}{3} x < 3(x - 9)
\][/tex]

Simplifying gives:

[tex]\[
18 - 2x < 3x - 27
\][/tex]

2. Rearrange Terms:
Next, we'll move all the terms involving [tex]\(x\)[/tex] to one side of the inequality and constants to the other side. To do this, add [tex]\(2x\)[/tex] to both sides and add 27 to both sides:

[tex]\[
18 + 27 < 3x + 2x
\][/tex]

Simplifying yields:

[tex]\[
45 < 5x
\][/tex]

3. Solve for [tex]\(x\)[/tex]:
Now, divide both sides of the inequality by 5 to solve for [tex]\(x\)[/tex]:

[tex]\[
\frac{45}{5} < x
\][/tex]

Simplifying gives:

[tex]\[
9 < x
\][/tex]

Which can also be written as:

[tex]\[
x > 9
\][/tex]

Therefore, the inequality is equivalent to [tex]\(x > 9\)[/tex].