College

A person pulls a toboggan for a distance of 37.9 m along the snow with a rope directed 32.8° above the snow. The tension in the rope is 105 N.

(a) How much work is done on the toboggan by the tension force?

(b) How much work is done if the same tension is directed parallel to the snow?

Answer :

a) Horizontal component of tension force = (cos 30) x 95, = 82.27N.
Work = (82.27 x 20) = 1,645.4 joules.
b) (20 x 95) = 1,900 joules.

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