Answer :
Final answer:
The mEq of sodium lactate (Na C3H5O3) in the Lactated Ringer's intravenous solution is approximately 347.79 mEq.
Explanation:
To calculate the mEq of sodium lactate (Na C3H5O3), we need to follow these steps:
- Calculate the molar mass of sodium lactate (Na C3H5O3). The molar mass of sodium (Na) is 22.99 g/mol, carbon (C) is 12.01 g/mol, hydrogen (H) is 1.01 g/mol, and oxygen (O) is 16.00 g/mol. Adding these atomic masses together, we get:
Molar mass of sodium lactate (Na C3H5O3) = (22.99 g/mol) + (3 * 12.01 g/mol) + (5 * 1.01 g/mol) + (3 * 16.00 g/mol) = 112.09 g/mol
- Calculate the concentration of sodium lactate in the solution. The concentration can be determined by dividing the mass of sodium lactate in the solution by the volume of the solution. In this case, the mass of sodium lactate is 310 mg and the volume of the solution is 100 mL:
Concentration of sodium lactate = (310 mg) / (100 mL) = 3.1 mg/mL
- Calculate the mEq of sodium lactate using the formula:
mEq = (concentration in mg/mL) x (molar mass in mg/mEq) x (volume in mL)
Substituting the values:
mEq = (3.1 mg/mL) x (112.09 mg/mEq) x (100 mL) = 347.79 mEq
Therefore, the mEq of sodium lactate (Na C3H5O3) in the Lactated Ringer's intravenous solution is approximately 347.79 mEq.
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