Answer :
To find the potential energy of a 25 kg bicycle resting at the top of a hill 3 meters high, we use the formula for potential energy:
[tex]\[ \text{Potential Energy (PE)} = m \times g \times h \][/tex]
where:
- [tex]\( m \)[/tex] is the mass in kilograms (kg),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex]),
- [tex]\( h \)[/tex] is the height in meters (m).
Let's use these values in the formula:
1. Identify the mass (m): The mass of the bicycle is 25 kg.
2. Identify the acceleration due to gravity (g): The standard value is [tex]\( 9.8 \, \text{m/s}^2 \)[/tex].
3. Identify the height (h): The height of the hill is 3 m.
Now, substitute these values into the formula:
[tex]\[ \text{PE} = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
4. Calculate the potential energy:
- First, multiply the mass by the acceleration due to gravity:
[tex]\[ 25 \times 9.8 = 245 \][/tex]
- Next, multiply the result by the height:
[tex]\[ 245 \times 3 = 735 \][/tex]
Therefore, the potential energy of the bicycle at the top of the hill is [tex]\( 735 \, \text{Joules (J)} \)[/tex].
So, the correct answer is 735 J.
[tex]\[ \text{Potential Energy (PE)} = m \times g \times h \][/tex]
where:
- [tex]\( m \)[/tex] is the mass in kilograms (kg),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex]),
- [tex]\( h \)[/tex] is the height in meters (m).
Let's use these values in the formula:
1. Identify the mass (m): The mass of the bicycle is 25 kg.
2. Identify the acceleration due to gravity (g): The standard value is [tex]\( 9.8 \, \text{m/s}^2 \)[/tex].
3. Identify the height (h): The height of the hill is 3 m.
Now, substitute these values into the formula:
[tex]\[ \text{PE} = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
4. Calculate the potential energy:
- First, multiply the mass by the acceleration due to gravity:
[tex]\[ 25 \times 9.8 = 245 \][/tex]
- Next, multiply the result by the height:
[tex]\[ 245 \times 3 = 735 \][/tex]
Therefore, the potential energy of the bicycle at the top of the hill is [tex]\( 735 \, \text{Joules (J)} \)[/tex].
So, the correct answer is 735 J.
