Answer :
The equation y = x + (the value you calculated for b) on the same graph where you plotted the scatter diagram.
The correct scatter diagram and the least-squares regression line for the given data set is shown below.
(a) The scatter diagram is shown below,
There is a strong negative relationship appears to exist between x and y.
(b) The least-squares regression line is given by,
[tex]$$y = a + bx$$[/tex]
where, a is the y-intercept and b is the slope.
We know that,
a = y - (b * x)
where y is the mean of y and x is the mean of x.
Given the values you provided:
x = 3.8333
sx = 2.0412
y = 4.0167
sy = 1.3393
r = -0.8986
[tex]$$b = \frac{r_{xy}sy}{sx}$$$$a = \bar{y} - b \bar{x}$$[/tex]
where, rxy is the correlation coefficient, sx and sy are the standard deviation of x and y respectively,
[tex]$\bar{x}$ and $\bar{y}$[/tex] are the mean of x and y respectively.
Therefore, we have, b = -2.758 and a = 12.033y
= 12.033 - 2.758x
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