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A buck-boost converter is driven by a battery with a voltage of 100V and operates in continuous current mode, supplying a load resistor of [tex]R = 700 \, \Omega[/tex]. Calculate the load RMS voltage, load RMS current, and the input average current for a duty cycle of 75%.

Answer :

The load output voltage is 400V, the load output current is approximately 0.571A, and the input average current is approximately 0.143A.

In a buck-boost converter, the load output voltage can be calculated using the formula:

Vout = Vin * (1 / (1 - D))

Where:

  • Vout is the load output voltage
  • Vin is the input voltage (100V in this case)
  • D is the duty cycle (75% in this case)

Substituting the given values into the formula:

Vout = 100V * (1 / (1 - 0.75))

Vout = 100V * (1 / 0.25)

Vout = 100V * 4

Vout = 400V

The load output voltage is 400V.

The load output current can be calculated using the formula:

Iout = Vout / R

Where:

  • Iout is the load output current
  • Vout is the load output voltage (400V in this case)
  • R is the load resistor (700Ω in this case)

Substituting the given values into the formula:

Iout = 400V / 700Ω

Iout ≈ 0.571A

The load output current is approximately 0.571A.

The input average current can be calculated using the formula:

Iavg = (1 - D) * Iout

Where:

  • Iavg is the input average current
  • D is the duty cycle (75% in this case)
  • Iout is the load output current (0.571A in this case)

Substituting the given values into the formula:

Iavg = (1 - 0.75) * 0.571A

Iavg = 0.25 * 0.571A

Iavg ≈ 0.143A

The input average current is approximately 0.143A.

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