A buck-boost converter has the following parameters:

- [tex]V_s = 12 \text{ V}[/tex]
- [tex]D = 0.6[/tex]
- [tex]R = 10 \, \Omega[/tex]
- [tex]L = 10 \, \mu \text{H}[/tex]
- [tex]C = 20 \, \mu \text{F}[/tex]
- Switching frequency: [tex]200 \, \text{kHz}[/tex]

Draw and label neatly the following:

i. The buck-boost converter circuit diagram.

ii. The waveforms for [tex]V[/tex], [tex]I[/tex], [tex]I_L[/tex], and [tex]I_C[/tex].

Answer :

A buck-boost converter is a DC-DC power converter that allows the voltage at its output to be adjusted at will from a voltage greater than the input voltage to a voltage less than the input voltage.

Buck-boost converters are used to power various types of electronic equipment, including audio amplifiers, LED lighting systems, and portable electronic devices. The design and analysis of the buck-boost converter are based on the following parameters: Vs = 12V: This is the input voltage to the converted rd. = 0.6: This is the duty cycle of the switch, which determines how long the switch is closed. R = 10 Ω:

This is the resistance of the load that the converter is powering .L = 10 Uh: This is the inductance of the inductor that the converter uses to store and release energy. C = 20 uF: This is the capacitance of the capacitor that the converter uses to store energy. fsw = 200 kHz: This is the switching frequency of the converter, which is the frequency at which the switch is opened and closed to control the output voltage. Draw and label the following:1. The buck-boost converter:2. Waveforms for V, I, I, Ic: The diagram of the buck-boost converter and the waveforms of V, I, I, .

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