Answer :
Final answer:
The component of the weight of the box along the inclined surface is approximately 108 N.
Explanation:
When an object rests on an inclined plane, its weight can be resolved into two components: a perpendicular component and a parallel component. The perpendicular component, which acts normal to the surface, is equal in magnitude to the normal force. The parallel component, which acts along the surface, can be determined using trigonometry.
In this case, the angle of the inclined surface is given as 52°. To find the component of the weight along the surface, we can use the equation: w = mg sinθ, where w is the component of weight along the surface, m is the mass of the box, g is the acceleration due to gravity (approximately 9.8 m/s²), and θ is the angle of the inclined surface.
Plug in the values: m = 14 kg, g = 9.8 m/s², and θ = 52°.
w = 14 kg * 9.8 m/s² * sin(52°)
Using a calculator, we find that w ≈ 108 N.
