Answer :
Sure! Let's solve the problem step-by-step.
We are given that the sum of two consecutive numbers is 157. We can represent the first number as [tex]\( n \)[/tex]. The next consecutive number is [tex]\( n + 1 \)[/tex]. Together, their sum can be written as:
[tex]\[ n + (n + 1) = 157 \][/tex]
Simplifying the equation, we get:
[tex]\[ 2n + 1 = 157 \][/tex]
Now, let's solve for [tex]\( n \)[/tex]:
1. Subtract 1 from both sides of the equation:
[tex]\[ 2n = 157 - 1 \][/tex]
[tex]\[ 2n = 156 \][/tex]
2. Divide both sides by 2 to find [tex]\( n \)[/tex]:
[tex]\[ n = \frac{156}{2} \][/tex]
[tex]\[ n = 78 \][/tex]
So, the first number is 78. Therefore, the correct answer is:
B. 78
We are given that the sum of two consecutive numbers is 157. We can represent the first number as [tex]\( n \)[/tex]. The next consecutive number is [tex]\( n + 1 \)[/tex]. Together, their sum can be written as:
[tex]\[ n + (n + 1) = 157 \][/tex]
Simplifying the equation, we get:
[tex]\[ 2n + 1 = 157 \][/tex]
Now, let's solve for [tex]\( n \)[/tex]:
1. Subtract 1 from both sides of the equation:
[tex]\[ 2n = 157 - 1 \][/tex]
[tex]\[ 2n = 156 \][/tex]
2. Divide both sides by 2 to find [tex]\( n \)[/tex]:
[tex]\[ n = \frac{156}{2} \][/tex]
[tex]\[ n = 78 \][/tex]
So, the first number is 78. Therefore, the correct answer is:
B. 78
