Answer :
Final answer:
The cost of the wine in the bottle is $9.50. This was calculated using basic algebra to solve given two equations: the total cost of the wine and the bottle ($10), and that the wine is $9 more expensive than the bottle.
Explanation:
The subject of this particular question is Mathematics, specifically an example of basic algebraic reasoning. The question says that the wine is worth $9 more than the bottle.
Given that the complete package (wine and bottle together) costs $10, we can create an equation to solve for the value of the wine itself. Let's denote the cost of the bottle as B and the cost of the wine as W.
According to the information given, we have two equations:
B + W = $10 (the total cost)
and
W = B + $9 (wine is $9 more expensive than the bottle).
We can solve these equations by substitution, from the second equation we substitute B in the first one with W - $9.
Therefore:
= (W - $9) + W
= $10.
Solving this equation yields W=$9.50. Therefore, the wine itself is worth $9.50.
Learn more about the topic of Algebra here:
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