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------------------------------------------------ A block of mass 14.9 kg is pulled to the right by an applied force of 39.4 N. If it moves with constant velocity, how much friction must be present?

We can solve this problem by applying Newton's 2nd law of motion: in fact, the net force acting on the block is equal to the product between its mass and its acceleration. So we can write

[tex]\sum F = ma[/tex]

where

[tex]\sum F[/tex] is the net force

m is the mass

a is the acceleration

Here we know that the box is moving with constant velocity, so its acceleration is zero:

[tex]a=0[/tex]

This means that the net force is also zero:

[tex]\sum F=0[/tex]

The net force on the block is given by the applied force, forward, and the frictional force, backward:

[tex]\sum F = F_a-F_f=0[/tex]

where

[tex]F_a=39.4 N[/tex] is the applied force

[tex]F_f[/tex] is the frictional force

Therefore, solving for [tex]F_f[/tex],

[tex]F_f=F_a=39.4 N[/tex]

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