Answer :
Final answer:
To find the grams of PbO that should form, balance the equation first. Then, use stoichiometric ratios to calculate the grams of PbO formed by converting the given masses of PbS and O2 to moles and using the mole ratios from the balanced equation. Finally, multiply the moles of PbO by the molar mass to find the grams of PbO formed.
Explanation:
To find the grams of PbO that should form, we need to balance the equation first. Balancing the equation will give us the stoichiometric coefficients, which represent the mole ratios of the reactants and products.
For the given equation:
PbS(s) + O2(g) → PbO(s) + SO2(g)
The balanced equation is:
2PbS(s) + 3O2(g) → 2PbO(s) + 2SO2(g)
Now, we can use the stoichiometric ratios to calculate the grams of PbO formed.
First, determine the moles of PbS and O2:
Moles of PbS = mass of PbS (g) / molar mass of PbS
Moles of O2 = mass of O2 (g) / molar mass of O2
Next, use the stoichiometric ratio to find the moles of PbO produced.
Moles of PbO = Moles of PbS (from the balanced equation) × (2 mol PbO) / (2 mol PbS)
Finally, calculate the grams of PbO formed.
Grams of PbO = Moles of PbO × molar mass of PbO
Substitute the given mass values for PbS and O2 into the above equations to find the grams of PbO formed.
I hope this helps! Let me know if you have any further questions.
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