Answer :
Final answer:
The reaction at the right-hand support for the given conditions is approximately 7139 lb.
Explanation:
To calculate the reaction at the right-hand support, we need to consider the equilibrium of forces and moments.
First, let's calculate the reaction at the left-hand support. Since the beam is simply supported at the ends, the reaction at the left-hand support is equal to the sum of the concentrated load and the uniform load multiplied by their respective distances from the left-hand end of the beam:
Reaction at left-hand support = Concentrated load + Uniform load * Distance
Plugging in the values:
Reaction at left-hand support = 10,000 lb + 900 plf * 5 ft
Next, we can calculate the reaction at the right-hand support by considering the equilibrium of moments about the left-hand support:
Reaction at right-hand support * 36 ft = Total bending moment at intermediate support
Plugging in the values:
Reaction at right-hand support * 36 ft = -45,820 ft-lb
Solving for the reaction at the right-hand support:
Reaction at right-hand support = -45,820 ft-lb / 36 ft
Finally, we can convert the reaction from ft-lb to lb:
Reaction at right-hand support = -45,820 ft-lb / 36 ft * 1 lb/ft
Therefore, the reaction at the right-hand support is approximately 7139 lb.
Learn more about reaction at the right-hand support of a beam with a uniform load and a concentrated load here:
https://brainly.com/question/31425190
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Final answer:
The reaction at the right-hand support for the given conditions is approximately 7139 lb.
Explanation:
To calculate the reaction at the right-hand support, we need to consider the equilibrium of forces and moments.
First, let's calculate the reaction at the left-hand support. Since the beam is simply supported at the ends, the reaction at the left-hand support is equal to the sum of the concentrated load and the uniform load multiplied by their respective distances from the left-hand end of the beam:
Reaction at left-hand support = Concentrated load + Uniform load * Distance
Plugging in the values:
Reaction at left-hand support = 10,000 lb + 900 plf * 5 ft
Next, we can calculate the reaction at the right-hand support by considering the equilibrium of moments about the left-hand support:
Reaction at right-hand support * 36 ft = Total bending moment at intermediate support
Plugging in the values:
Reaction at right-hand support * 36 ft = -45,820 ft-lb
Solving for the reaction at the right-hand support:
Reaction at right-hand support = -45,820 ft-lb / 36 ft
Finally, we can convert the reaction from ft-lb to lb:
Reaction at right-hand support = -45,820 ft-lb / 36 ft * 1 lb/ft
Therefore, the reaction at the right-hand support is approximately 7139 lb.
Learn more about reaction at the right-hand support of a beam with a uniform load and a concentrated load here:
https://brainly.com/question/31425190
#SPJ14