A battery of 6 V is connected in series with resistors of 0.1 ohm, 0.15 ohm, 0.2 ohm, 0.25 ohm, and 6 ohm. How much current would flow through the 0.3 ohm resistor?

To determine the current through a 0.3 ohm resistor in a series circuit with a 6V battery and other resistors, sum up the resistances, apply Ohm's Law, and find that the current is approximately 0.895 A.

Explanation:

To calculate the current that would flow through a 0.3 ohm resistor in a series circuit with a 6V battery, we first need to find the total resistance in the circuit.

Since the resistors are in series, the total resistance (RT) is the sum of all individual resistances. Thus, RT = 0.1 + 0.15 + 0.2 + 0.25 + 6 = 6.7 ohms.

According to Ohm's Law, which states that I = V/R, where I is the current, V is the voltage, and R is the resistance, we can find the current flowing through the circuit by I = 6V / 6.7Ω.

Calculating this gives us a current I ≈ 0.895 A (to three significant figures).

Since the resistors are in series, the same current flows through all of them, including the 0.3 ohm resistor that is not listed in the original circuit but assumed to be there.

The current through the 0.3 ohm resistor, if it were in the circuit, would be 0.895 A.