High School

A 65 kg dog running at 10 m/s crashes into a sliding glass door in 0.08 seconds. What is the force of impact?

A. 8125 N
B. 813 N
C. 1250 N
D. 1500 N

Answer :

Final answer:

The force of impact exerted by a 65 kg dog running into a door at 10 m/s and stopping in 0.08s is calculated using Newton's second law to be 8125 N, corresponding to answer choice A.

Explanation:

The question asks for the force of impact a 65 kg dog exerts when running into a sliding glass door at 10 m/s and coming to a stop in 0.08s. To calculate the force of impact, we can use the formula derived from Newton's second law, F = (m × Δv) / Δt, where m is the mass, Δv is the change in velocity, and Δt is the change in time. Since the dog comes to a stop, the change in velocity is equal to the initial velocity, hence Δv = 10 m/s, and Δt is 0.08 seconds.

Now, substituting the values we get:

  • Δv = 10 m/s
  • Δt = 0.08s
  • m = 65 kg

F = (65 kg × 10 m/s) / 0.08s = 8125 N

Therefore, the correct answer is A. 8125 N.