Answer :
Final answer:
The force of impact exerted by a 65 kg dog running into a door at 10 m/s and stopping in 0.08s is calculated using Newton's second law to be 8125 N, corresponding to answer choice A.
Explanation:
The question asks for the force of impact a 65 kg dog exerts when running into a sliding glass door at 10 m/s and coming to a stop in 0.08s. To calculate the force of impact, we can use the formula derived from Newton's second law, F = (m × Δv) / Δt, where m is the mass, Δv is the change in velocity, and Δt is the change in time. Since the dog comes to a stop, the change in velocity is equal to the initial velocity, hence Δv = 10 m/s, and Δt is 0.08 seconds.
Now, substituting the values we get:
- Δv = 10 m/s
- Δt = 0.08s
- m = 65 kg
F = (65 kg × 10 m/s) / 0.08s = 8125 N
Therefore, the correct answer is A. 8125 N.
