College

At the gym, Jasper was able to bench press 224 pounds, which was [tex]\frac{7}{8}[/tex] of the weight that Balin was able to bench press. Which shows the correct equation and value of [tex]x[/tex], the weight that Balin could bench press?

A. [tex]\frac{7}{8}x = 224 ; x = 196[/tex] pounds
B. [tex]\frac{7}{8}x = 224 ; x = 256[/tex] pounds
C. [tex]\frac{7}{8} = \frac{x}{224} ; x = 196[/tex] pounds
D. [tex]\frac{7}{8} = \frac{x}{224} ; x = 256[/tex] pounds

Answer :

To solve this problem, let's set up the equation based on the information given in the question:

Jasper was able to bench press 224 pounds, which was [tex]\(\frac{7}{8}\)[/tex] of the weight that Balin could bench press. We need to find out how much Balin could bench press, represented by [tex]\(x\)[/tex].

The equation based on the problem is:

[tex]\[
\frac{7}{8} \times x = 224
\][/tex]

To solve for [tex]\(x\)[/tex], we need to isolate it. We can do this by multiplying both sides of the equation by the reciprocal of [tex]\(\frac{7}{8}\)[/tex], which is [tex]\(\frac{8}{7}\)[/tex]:

[tex]\[
x = 224 \times \frac{8}{7}
\][/tex]

Now, let's perform the multiplication:

1. First, calculate [tex]\(224 \times 8\)[/tex]:
[tex]\[
224 \times 8 = 1792
\][/tex]

2. Now, divide the result by 7:
[tex]\[
1792 \div 7 = 256
\][/tex]

So, the correct weight that Balin could bench press is [tex]\(x = 256\)[/tex] pounds.

Therefore, the correct equation and value of [tex]\(x\)[/tex] is:

[tex]\(\frac{7}{8}x = 224 ; x = 256\)[/tex] pounds