Answer :
Final answer:
The molar mass of magnesium nitrate[tex](Mg(NO_3)_2)[/tex] is 148.3 g/mol. This is calculated as the sum of the molar mass of Magnesium (Mg), twice that of Nitrogen (N), and six times that of Oxygen (O). A 4.50-g sample of magnesium nitrate containing 0.0304 mol of the compound conforms to this molar mass.
Explanation:
The question is asking for the molar mass of magnesium nitrate [tex](Mg(NO_3)_2)[/tex]. Molar mass is the weight of one mole ([tex]6.022 x 10^23[/tex]molecules) of any chemical compounds. The molar mass of magnesium nitrate can be calculated as the sum of the molar mass of Magnesium (Mg) and twice the molar mass of Nitrogen (N) and six times the molar mass of Oxygen (O).
The attendant values are:
- Mg = 24.3 g/mol
- N = 14.0 g/mol
- O = 16.0 g/mol[tex](6.022 x 10^23 molecules)[/tex]
Therefore, the molar mass of
magnesium nitrate
is = [24.3 + 2*(14.0) + 6*(16.0)] g/mol = 148.3 g/mol
If a 4.50-g sample of magnesium nitrate contains 0.0304 mol of the compound, this is consistent with the molar mass calculation as (4.50 g) / (0.0304 mol) = 148.1 g/mol, which is very close to the calculated molar mass of 148.3 g/mol.
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