High School

A 30 kg box is being pushed across the floor with a coefficient of friction, \( \mu = 0.32 \). What is the force of friction acting on this box?

A. -40 N
B. -94 N
C. -165 N
D. -392 N

Answer :

The force of friction acting on the box can be determined using the equation: Frictional force = coefficient of friction × normal force.

The correct option is B.

In this case, the normal force is equal to the weight of the box, which can be calculated using the equation:
Weight = mass × acceleration due to gravity Given that the mass of the box is 30 kg, and the acceleration due to gravity is approximately 9.8 m/s^2, we can calculate the weight of the box as:
Weight = 30 kg × 9.8 m/s^2

= 294 N
Now, we need to find the coefficient of friction. The coefficient of friction, denoted as "u," represents the frictional force between two surfaces in contact. In this case, the coefficient of friction is given as 0.32.
Using the formula mentioned earlier, we can calculate the frictional force:
Frictional force = 0.32 × 294 N

= 94.08 N
Rounding to two decimal places, the force of friction acting on the box is approximately 94 N. Therefore, the correct answer is B) -94N.

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Final answer:

The force of friction acting on a 30 kg box with a coefficient of friction of 0.32 is found by multiplying the coefficient of friction by the weight of the box. The normal force equals the weight, and the result is 94.08 N, typically represented as -94 N to indicate its opposing direction to motion. The correct answer is B: -94 N.

Explanation:

To determine the force of friction acting on a 30 kg box with a coefficient of friction (μ) of 0.32, we can use the formula for frictional force which is:

Ffriction = μ * Fnormal

Here, Fnormal is the normal force, and on a flat surface, it is equal to the weight of the box, which is the product of its mass (m) and the acceleration due to gravity (g, approximately 9.8 m/s2). The weight of the box is therefore 30 kg * 9.8 m/s2 = 294 N.

Now, we calculate the frictional force:

Ffriction = 0.32 * 294 N = 94.08 N

The force of friction is typically expressed as a positive number, but since it is a force that resists motion, when considered in equations of motion, it is often given a negative value to indicate that it is opposite to the direction of applied force. Therefore, the answer is -94 N, which corresponds to option B.