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A 0.50 kg object is attached to a spring with a force constant of 157 N/m, allowing the object to move on a horizontal frictionless surface. The object is released from rest when the spring is compressed by 0.19 m.

(a) Find the force on the object.
(b) Find its acceleration at that instant.

Answer :

Explanation:

We have,

Mass of an object is 0.5 kg

Force constant of the spring is 157 N/m

The object is released from rest when the spring is compressed 0.19 m.

(A) The force acting on the object is given by :

F = kx

[tex]F=157\times 0.19\\\\F=29.83\ N[/tex]

(B) The force is simply given by :

F = ma

a is acceleration at that instant

[tex]a=\dfrac{F}{m}\\\\a=\dfrac{29.83}{0.5}\\\\a=59.66\ m/s^2[/tex]

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