Answer :
No, ROH (alcohol) is not a possible product in the reaction of the Grignard reagent (RMgBr) with water.
The reaction between a Grignard reagent (RMgBr) and water proceeds through a specific mechanism called the "Grignard reaction." In this reaction, the Grignard reagent acts as a strong nucleophile, attacking the electrophilic carbon of the carbonyl compound.
When a Grignard reagent reacts with water, it undergoes a two-step process. In the first step, the Grignard reagent reacts with water to form an alkoxide intermediate:
RMgBr + H2O → R-O-MgBr + HBr
In the second step, the alkoxide intermediate reacts with another molecule of the Grignard reagent, resulting in the formation of the desired alcohol:
R-O-MgBr + RMgBr → R-O-R + MgBr2
As seen from the mechanism, the Grignard reagent reacts with water to form an alkoxide (R-O-MgBr) intermediate, which then reacts further to produce the alcohol (R-O-R). Thus, the formation of ROH as a direct product is not observed in this reaction.
Therefore, ROH (alcohol) is not a possible product, even in small amounts, in the reaction of the Grignard reagent with water.
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