High School

20. Chemistry

The half-life of iodine-124 is 4 days. A technician measures a 40-mCi sample of iodine-124.

a. How many half-lives of iodine-124 occur in 16 days?

b. How much iodine-124 is in the sample 16 days after the technician measures the original sample?

Answer :

The amount of iodine-124 left after 16 days when the technician measured the original sample will be a/16.

What is an exponent?

Let a be the initial value and x be the number of days, 1/2 be the half-life factor, and y be the amount left after x days.

The exponent is given as,

[tex]\rm y = a \left ( \dfrac{1}{2} \right )^{\dfrac{x}{4}}[/tex]

Chemistry Iodine-124 has a half-life of four days. Iodine-124 sample of 40 mCi is measured by a technician.

The amount of iodine-124 left after 16 days when the technician measured the original sample will be

[tex]\rm y = a \left ( \dfrac{1}{2} \right )^{\dfrac{16}{4}}\\\\\rm y = a \left ( \dfrac{1}{2} \right )^{4}\\\\\rm y = a \left ( \dfrac{1}{16} \right )\\\\\rm y = \dfrac{a}{16}[/tex]

The amount of iodine-124 left after 16 days when the technician measured the original sample will be a/16.

More about the exponent link is given below.

https://brainly.com/question/5497425

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