Answer :
The pressure of the oxygen in the cylinder can be calculated using the ideal gas law PV = nRT. Therefore, the pressure of the oxygen in the cylinder will be 125 atm.
As we know that,
PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant and T is the temperature (assumed constant). We can also use the proportionality relationship between the initial and final pressures and volumes, P1V1 = P2V2.
Given:
V1 = 2500 L
P1 = 1.00 atm
V2 = 20.0 L
We can rearrange the proportionality equation to find P2:
P2 = P1 * V1/V2
So P2 = 1.00 atm * 2500 L / 20.0 L = 125 atm
Therefore, the pressure of the oxygen in the cylinder will be 125 atm.
It is important to note that compressing a gas to such high pressures is not safe and could cause the cylinder to explode. In practice, this process will be done in steps and in controlled conditions.
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