College

15. Which equation, when solved, results in a different value of [tex]$x$[/tex] than the other three?

Show your work:

A. [tex]$8.3 = -0.6 x + 11.3$[/tex]

B. [tex]$11.3 = 8.3 + 0.6 x$[/tex]

C. [tex]$11.3 - 0.6 x = 8.3$[/tex]

D. [tex]$8.3 - 0.6 x = 11.3$[/tex]

Answer :

To find which equation results in a different value of [tex]\( x \)[/tex], we'll solve each equation separately and compare their solutions.

Let's solve each equation step-by-step:

Equation A:
[tex]\[ 8.3 = -0.6x + 11.3 \][/tex]

1. Subtract 11.3 from both sides:
[tex]\[ 8.3 - 11.3 = -0.6x \][/tex]
[tex]\[ -3.0 = -0.6x \][/tex]

2. Divide both sides by -0.6 to solve for [tex]\( x \)[/tex]:
[tex]\[ x = \frac{-3.0}{-0.6} \][/tex]
[tex]\[ x = 5.0 \][/tex]

Equation B:
[tex]\[ 11.3 = 8.3 + 0.6x \][/tex]

1. Subtract 8.3 from both sides:
[tex]\[ 11.3 - 8.3 = 0.6x \][/tex]
[tex]\[ 3.0 = 0.6x \][/tex]

2. Divide both sides by 0.6 to solve for [tex]\( x \)[/tex]:
[tex]\[ x = \frac{3.0}{0.6} \][/tex]
[tex]\[ x = 5.0 \][/tex]

Equation C:
[tex]\[ 11.3 - 0.6x = 8.3 \][/tex]

1. Subtract 11.3 from both sides:
[tex]\[ -0.6x = 8.3 - 11.3 \][/tex]
[tex]\[ -0.6x = -3.0 \][/tex]

2. Divide both sides by -0.6 to solve for [tex]\( x \)[/tex]:
[tex]\[ x = \frac{-3.0}{-0.6} \][/tex]
[tex]\[ x = 5.0 \][/tex]

Equation D:
[tex]\[ 8.3 - 0.6x = 11.3 \][/tex]

1. Subtract 8.3 from both sides:
[tex]\[ -0.6x = 11.3 - 8.3 \][/tex]
[tex]\[ -0.6x = 3.0 \][/tex]

2. Divide both sides by -0.6 to solve for [tex]\( x \)[/tex]:
[tex]\[ x = \frac{3.0}{-0.6} \][/tex]
[tex]\[ x = -5.0 \][/tex]

After solving each equation, we find the values for [tex]\( x \)[/tex]:

- Equation A: [tex]\( x = 5.0 \)[/tex]
- Equation B: [tex]\( x = 5.0 \)[/tex]
- Equation C: [tex]\( x = 5.0 \)[/tex]
- Equation D: [tex]\( x = -5.0 \)[/tex]

The equation that results in a different value for [tex]\( x \)[/tex] than the rest is Equation D, which gives [tex]\( x = -5.0 \)[/tex].