Answer :
to prepare a 1.5 M NaOH solution based on the volume and assuming a density of 1 g/mL, we would require approximately 59.985 grams of NaOH.
To prepare a 1.5 M solution of sodium hydroxide (NaOH), we need to determine the weight of NaOH required based on the volume of solution we want to prepare and the assumed density.
The molarity (M) of a solution is defined as the number of moles of solute per liter of solution. In this case, we want to prepare a 1.5 M solution of NaOH.
To calculate the weight of NaOH required, we need to know the volume of the solution we want to prepare and the density of the solution. However, the density of the solution is not provided in the question.
Assuming a density of 1 g/mL for a 1.5 M NaOH solution is a reasonable approximation. However, it's important to note that the actual density may vary depending on the concentration and temperature of the solution.
The molar mass of NaOH is 22.99 g/mol for sodium (Na), 16.00 g/mol for oxygen (O), and 1.01 g/mol for hydrogen (H). Adding these together gives a molar mass of 39.99 g/mol for NaOH.
To calculate the weight of NaOH needed, we use the formula:
Weight (g) = molarity (mol/L) * volume (L) * molar mass (g/mol)
For example, if we want to prepare 1 liter of a 1.5 M NaOH solution, the weight of NaOH required would be:
Weight (g) = 1.5 mol/L * 1 L * 39.99 g/mol = 59.985 g
Therefore, to prepare a 1.5 M NaOH solution based on the volume and assuming a density of 1 g/mL, we would require approximately 59.985 grams of NaOH.
However, it's important to note that the actual weight may differ if the actual density of the solution is significantly different from the assumed value.
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