College

You operate a fresh fruit and vegetable market. For normal shipments, about 9.0% of the peaches are spoiled when they reach your market. You anticipate a busy weekend and would like to have 100 pounds of peaches to sell.

To have 100 pounds of peaches considering the spoilage rate, how many pounds should you order?

A. 101 lbs.
B. 105 lbs.
C. 109 lbs.
D. 110 lbs.
E. 112 lbs.

Answer :

Given:

Spoilage rate of fruits = 9% = 0.09

To find:

Amount of fruits to be order to have 100 pounds of peaches and considering the spoilage rate.

Solution:

Let the required amount of fruits you should order be x.

So, spoiled fruits = 9% of x = 0.09x

He would like to have 100 pounds of peaches to sell.

[tex]x-0.09x=100[/tex]

[tex]0.91x=100[/tex]

Divide both sides by 0.91.

[tex]x=\dfrac{100}{0.91}[/tex]

[tex]x=109.89[/tex]

[tex]x\approx 110[/tex]

The required amount of fruits to be order is 110 lbs. Therefore, the correct option is D.

Final answer:

To ensure having 100 pounds of sellable peaches, considering a spoilage rate of 9.0%, you must order approximately 109.89 pounds. Since you cannot order a fraction of a pound, it is necessary to round up to 110 pounds, so the correct answer is D. 110 lbs.

Explanation:

To determine how many pounds of peaches you should order to have 100 pounds of sellable peaches after accounting for a spoilage rate of 9.0%, you need to calculate the inverse percentage. The following steps explain how to do this:

Let x represent the total pounds of peaches you need to order.

Since 9.0% of the peaches will be spoiled, you'll have 91% of x pounds remaining for selling.

To find x, setup the equation 0.91x = 100 (because you want 100 pounds of non-spoiled peaches).

Divide both sides of the equation by 0.91 to solve for x.

x = 100 / 0.91, which calculates to approximately 109.89 pounds.

Since you can't order a fraction of a pound, you should round up to ensure you have at least 100 pounds of non-spoiled peaches. Thus, you need to order 110 pounds.

The correct answer is D. 110 lbs.