Answer :
To find out the weight of copper required for a 1.3 wt% copper in a 235 lb heat of aluminum-copper alloy, convert the weight percent into decimal form and multiply by the total weight. In this case, about 3.055 pounds of copper is required.
The student wishes to create a specific aluminum/copper alloy mix. This alloy is defined by being 1.3 weight percent (wt%) copper. To compute the needed weight of copper, we will multiply the total desired weight of the heat by the weight percent of copper.
This is done as follows:
- First convert the weight percent into decimal form. 1.3 wt% equals 0.013.
- Multiply the total weight of the alloy, 235 lb in this case, by the weight fraction of copper (0.013).
Doing this gives: 235 lb * 0.013 = 3.055 lb. So, you would need approximately 3.055 pounds of copper to achieve a mixture that is 1.3 wt% copper for a 235 lb heat.
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