Answer :
The machine can lift a mass of water of 500 g to a height of 1 meter in 5 seconds when dissipating 60 watts of power every minute, with gravity taken as 10 m/s squared (option b).
To solve this problem, we must use the formula for power (P), which is the rate of doing work or energy transferred per unit time, expressed as P = work/time.
Since power is given in watts and 1 watt is equal to 1 joule per second, we can calculate the total energy used by the machine in 5 seconds as follows: (60 watts) / (60 seconds/minute) * (5 seconds) = 5 joules.
Next, using the formula for gravitational potential energy (GPE), which is GPE = mgh (mass x gravity x height), and substituting the known values (g = 10 m/s2 and h = 1 m) we can solve for the mass (m) that corresponds to 5 joules of energy:
5 joules = m x 10 m/s2 x 1 m.
Solving for mass, we find m = 0.5 kg, which can be converted to grams (m x 1000) to give 500 g.
Therefore, the correct answer is b) 500 g.
