(You May Need to USE ASCII Table)

1. Write a line by line explanation to this program.

2. What does the program do?

3. What will be displayed?

.model small

.stack 100h

.386

.code

main proc

mov cl, 7aH

mov bl, 2

SHL BL,1

l:

call k

dec bl

jnz l

MOV DL, 0AH

call dEL

MOV DL, 44H

call dEL

MOV DL, 4FH

call dEL

MOV DL, 4EH

call dEL

MOV DL, 45H

call dEL

mov ax, 4c00h

int 21h

k proc

m:

mov ah, 1

int 21h

cmp al, CL

jnz m

sub cl,11

ret

k endp

dEL proc

mov ah,6

int 21h

ret

dEL endp

main endp

end main

Answer :

The program first loads the ASCII code for | into CL. Then, it sets BL to 2 and shifts it left by one, which gives us 4.

How to explain the information

The program then enters a loop where it calls the k procedure, decrements BL, and jumps back to the loop if BL is not zero. The k procedure reads a character from the keyboard and compares it to the value in CL. If the characters are not equal, the k procedure jumps back to the start of the procedure. Otherwise, the k procedure subtracts 11 from CL and returns.

The dEL procedure prints the character in DL. The program calls the dEL procedure 6 times, priIt begins by setting aside 100h (256 bytes) of stack space. It specifies the use of 386 instructions, indicating compatibility with the 80386 processor or higher. The program defines a procedure called "main" using the "proc" directiventing the characters "HONE" followed by a carriage return.

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