College

You encounter a specification that lists a Jominy distance of 12.7 mm and a bar diameter of 38.1 mm. What is the H coefficient for this?

Answer :

For a Jominy distance of 12.7 mm and a bar diameter of 38.1 mm, the H coefficient is approximately 5.08.

The H coefficient in Jominy hardenability testing represents the cooling rate at a specific distance from the quenched end of a Jominy test specimen. It is used to assess the hardenability of a material.

The H coefficient is calculated using the formula:

H = (d^2) / (t - d/2)

Where:

H = H coefficient

d = Jominy distance (in this case, 12.7 mm)

t = Bar diameter (in this case, 38.1 mm)

Substituting the given values into the formula, we have:

H = (12.7^2) / (38.1 - 12.7/2)

H = (161.29) / (38.1 - 6.35)

H = 161.29 / 31.75

H ≈ 5.08

Therefore, for a Jominy distance of 12.7 mm and a bar diameter of 38.1 mm, the H coefficient is approximately 5.08.

To know more about Jominy hardenability testing, visit: https://brainly.com/question/33368128

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