Answer :
To find the acceleration, we use Newton's second law, which states:
[tex]$$
F = m \cdot a
$$[/tex]
where
[tex]\( F \)[/tex] is the force applied,
[tex]\( m \)[/tex] is the mass, and
[tex]\( a \)[/tex] is the acceleration.
We are given:
- [tex]\( F = 172 \, \text{N} \)[/tex]
- [tex]\( m = 51 \, \text{kg} \)[/tex]
We can solve for [tex]\( a \)[/tex] by rearranging the equation:
[tex]$$
a = \frac{F}{m}
$$[/tex]
Substitute the given values:
[tex]$$
a = \frac{172}{51} \approx 3.37 \, \text{m/s}^2
$$[/tex]
Thus, the forward acceleration of the bicycle is approximately [tex]\( 3.37 \, \text{m/s}^2 \)[/tex], which corresponds to option D.
[tex]$$
F = m \cdot a
$$[/tex]
where
[tex]\( F \)[/tex] is the force applied,
[tex]\( m \)[/tex] is the mass, and
[tex]\( a \)[/tex] is the acceleration.
We are given:
- [tex]\( F = 172 \, \text{N} \)[/tex]
- [tex]\( m = 51 \, \text{kg} \)[/tex]
We can solve for [tex]\( a \)[/tex] by rearranging the equation:
[tex]$$
a = \frac{F}{m}
$$[/tex]
Substitute the given values:
[tex]$$
a = \frac{172}{51} \approx 3.37 \, \text{m/s}^2
$$[/tex]
Thus, the forward acceleration of the bicycle is approximately [tex]\( 3.37 \, \text{m/s}^2 \)[/tex], which corresponds to option D.