Answer :
The height of the triangle with a base of 8m and an area of 12m² is 3 meters.
To find the height of a triangle with a given base and area, we can use the formula for the area of a triangle:
[tex]\[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \][/tex]
Given that the base [tex]\( b \)[/tex] is 8m and the area [tex]\( A \)[/tex] is [tex]12m^2[/tex], we can plug these values into the formula and solve for the height ([tex]\( h \)[/tex]):
[tex]\[ 12 = \frac{1}{2} \times 8 \times h \][/tex]
Now, let's solve for [tex]\( h \)[/tex]:
[tex]\[ 12 = 4h \][/tex]
[tex]\[ h = \frac{12}{4} \][/tex]
[tex]\[ h = 3 \][/tex]
So, the height of the triangle is 3 meters.
To calculate the height of a triangle with a known base of 8m and area of 12m squared, we rearrange the area formula and find that the height is 3 meters.
To calculate the height of a triangle when the base and area are known, you can use the formula for the area of a triangle: Area = 1/2 * base * height. The area is given as 12 [tex]m^2[/tex] and the base is 8 m. To find the height, we need to rearrange the formula to solve for height.
So we have:
Area = 1/2 * base * height
12 [tex]m^2[/tex] = 1/2 * 8 m * height
12 [tex]m^2[/tex] = 4 m * height
height = 12 [tex]m^2[/tex] / 4 m
height = 3 m
Therefore, the height of the triangle is 3 meters.
