Answer :
Heat is needed to raise the temperature of the 0.015 Kg sample of lead by 10 degrees C is 19.2 J.
If the temperature of an object is high, then the heat contained by the object is very large. And vice versa if the temperature is low, the heat contained is small. The size of the heat required by an object (substance) depends on 3 factors: the mass of the substance, the type of substance (specific heat), and changes in temperature. So that mathematically it can be formulated:
Q = mc(ΔT)
Q is the required heat (J).
m is the mass of the object (kg).
c is the specific heat (J/kgC).
ΔT is the change in temperature (C).
The required energy input is given by
Q = mc(ΔT)
Q = (0.015kg)(128J/kg.°C)(10°C)
Q = 19.2 J
So, it takes 19.2 joules of heat to raise the temperature of 0.015 kg of the tin sample by 10 degrees Celsius.
Learn more about the Caloric change formula at https://brainly.com/question/22410367
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