College

Which polynomial equation has zeros of [tex]5[/tex], [tex]-3[/tex], and [tex]3[/tex]?

A. [tex]x^3 + 4x^2 + 4x - 45 = 0[/tex]
B. [tex]x^3 - 5x^2 - 9x + 45 = 0[/tex]
C. [tex]x^3 - 4x^2 + 4x + 45 = 0[/tex]
D. [tex]x^3 + 5x^2 - 9x - 45 = 0[/tex]
E. [tex]x^3 + 5x^2 + 4x + 45 = 0[/tex]

Answer :

To find a polynomial equation with given zeros of 5, -3, and 3, we start by understanding what these zeros mean in terms of factors of the polynomial. If a polynomial has zeros at [tex]\(x = 5\)[/tex], [tex]\(x = -3\)[/tex], and [tex]\(x = 3\)[/tex], then it can be represented by factors as follows:

- For zero at [tex]\(x = 5\)[/tex], the factor is [tex]\((x - 5)\)[/tex].
- For zero at [tex]\(x = -3\)[/tex], the factor is [tex]\((x + 3)\)[/tex].
- For zero at [tex]\(x = 3\)[/tex], the factor is [tex]\((x - 3)\)[/tex].

The polynomial is obtained by multiplying these factors together:

[tex]\[
(x - 5)(x + 3)(x - 3)
\][/tex]

First, we handle the multiplication of [tex]\((x + 3)(x - 3)\)[/tex], which is a difference of squares:

[tex]\[
(x + 3)(x - 3) = x^2 - 9
\][/tex]

Now, multiply this result by the remaining factor [tex]\((x - 5)\)[/tex]:

[tex]\[
(x - 5)(x^2 - 9) = x(x^2 - 9) - 5(x^2 - 9)
\][/tex]

[tex]\[
= x^3 - 9x - 5x^2 + 45
\][/tex]

Rearranging the terms, we get:

[tex]\[
x^3 - 5x^2 - 9x + 45
\][/tex]

This expression suggests that the polynomial equation with zeros at 5, -3, and 3 is:

[tex]\[
x^3 - 5x^2 - 9x + 45 = 0
\][/tex]

Among the given options, this matches with:

b. [tex]\(x^3 - 5x^2 - 9x + 45 = 0\)[/tex]

Therefore, the correct option is b.