Answer :
Sure! Let's solve this genetics problem step-by-step.
1. Understanding the Genotypes:
- A heterozygous male has the genotype Ww. This means he carries one dominant allele (W) and one recessive allele (w).
- A homozygous recessive female has the genotype ww, meaning both her alleles are recessive (w).
2. Creating a Punnett Square for Ww x ww:
- We'll create a grid to show the possible combinations of alleles from each parent.
- The male (Ww) can pass on either W or w.
- The female (ww) can only pass on a w.
```
W w
-------
w | Ww | ww
w | Ww | ww
```
- From this grid, we have two Ww combinations and two ww combinations. This means there are:
- 50% chance (2 out of 4 squares) for the offspring to be heterozygous Ww.
- 50% chance (also 2 out of 4 squares) for the offspring to be homozygous recessive ww.
3. Examining the Second Cross (Ww x WW):
- Now, consider crossing a heterozygous individual (Ww) with a homozygous dominant individual (WW).
```
W W
-------
W | WW | WW
w | Ww | Ww
```
- The possible offspring combinations are WW and Ww. This results in:
- 0% chance (no squares) for homozygous recessive offspring (ww).
Finally, putting these together:
- For the cross Ww with ww, 50% of the offspring will be heterozygous Ww.
- For the cross Ww with WW, 0% of the offspring will be homozygous recessive ww.
1. Understanding the Genotypes:
- A heterozygous male has the genotype Ww. This means he carries one dominant allele (W) and one recessive allele (w).
- A homozygous recessive female has the genotype ww, meaning both her alleles are recessive (w).
2. Creating a Punnett Square for Ww x ww:
- We'll create a grid to show the possible combinations of alleles from each parent.
- The male (Ww) can pass on either W or w.
- The female (ww) can only pass on a w.
```
W w
-------
w | Ww | ww
w | Ww | ww
```
- From this grid, we have two Ww combinations and two ww combinations. This means there are:
- 50% chance (2 out of 4 squares) for the offspring to be heterozygous Ww.
- 50% chance (also 2 out of 4 squares) for the offspring to be homozygous recessive ww.
3. Examining the Second Cross (Ww x WW):
- Now, consider crossing a heterozygous individual (Ww) with a homozygous dominant individual (WW).
```
W W
-------
W | WW | WW
w | Ww | Ww
```
- The possible offspring combinations are WW and Ww. This results in:
- 0% chance (no squares) for homozygous recessive offspring (ww).
Finally, putting these together:
- For the cross Ww with ww, 50% of the offspring will be heterozygous Ww.
- For the cross Ww with WW, 0% of the offspring will be homozygous recessive ww.
