High School

Which equation, when solved, results in a different value of [tex]x[/tex] than the other three?

A. [tex]8.3 = -0.6x + 11.3[/tex]

B. [tex]11.3 = 8.3 + 0.6x[/tex]

C. [tex]11.3 - 0.6x = 8.3[/tex]

D. [tex]8.3 - 0.6x = 11.3[/tex]

Answer :

Let's solve each of the equations step by step to find which equation results in a different value of [tex]\( x \)[/tex].

1. Equation 1: [tex]\( 8.3 = -0.6x + 11.3 \)[/tex]

- Start by isolating the variable term:
[tex]\[
-0.6x = 8.3 - 11.3
\][/tex]
[tex]\[
-0.6x = -3
\][/tex]
- Solve for [tex]\( x \)[/tex] by dividing both sides by [tex]\(-0.6\)[/tex]:
[tex]\[
x = \frac{-3}{-0.6} = 5
\][/tex]

2. Equation 2: [tex]\( 11.3 = 8.3 + 0.6x \)[/tex]

- Start by isolating the variable term:
[tex]\[
0.6x = 11.3 - 8.3
\][/tex]
[tex]\[
0.6x = 3
\][/tex]
- Solve for [tex]\( x \)[/tex] by dividing both sides by [tex]\(0.6\)[/tex]:
[tex]\[
x = \frac{3}{0.6} = 5
\][/tex]

3. Equation 3: [tex]\( 11.3 - 0.6x = 8.3 \)[/tex]

- Start by isolating the variable term:
[tex]\[
-0.6x = 8.3 - 11.3
\][/tex]
[tex]\[
-0.6x = -3
\][/tex]
- Solve for [tex]\( x \)[/tex] by dividing both sides by [tex]\(-0.6\)[/tex]:
[tex]\[
x = \frac{-3}{-0.6} = 5
\][/tex]

4. Equation 4: [tex]\( 8.3 - 0.6x = 11.3 \)[/tex]

- Start by isolating the variable term:
[tex]\[
-0.6x = 11.3 - 8.3
\][/tex]
[tex]\[
-0.6x = 3
\][/tex]
- Solve for [tex]\( x \)[/tex] by dividing both sides by [tex]\(-0.6\)[/tex]:
[tex]\[
x = \frac{3}{-0.6} = -5
\][/tex]

Reviewing the solutions, we find:

- Equations 1, 2, and 3 all have a solution of [tex]\( x = 5 \)[/tex].
- Equation 4 has a different solution of [tex]\( x = -5 \)[/tex].

Thus, the equation [tex]\( 8.3 - 0.6x = 11.3 \)[/tex] results in a different value of [tex]\( x \)[/tex] than the others.