Answer :
To solve the given system of equations using elimination, we follow these steps:
We have the system:
1. [tex]\(5a + 5b = 25\)[/tex]
2. [tex]\(-5a + 5b = 35\)[/tex]
The elimination method involves adding the two equations to eliminate one of the variables. Let's add these equations together:
[tex]\[
(5a + 5b) + (-5a + 5b) = 25 + 35
\][/tex]
Simplifying this, we see that the [tex]\(5a\)[/tex] and [tex]\(-5a\)[/tex] terms cancel each other out:
[tex]\[
0a + 10b = 60
\][/tex]
This simplifies to:
[tex]\[
10b = 60
\][/tex]
So, the resulting equation when elimination is used is [tex]\(10b = 60\)[/tex].
We have the system:
1. [tex]\(5a + 5b = 25\)[/tex]
2. [tex]\(-5a + 5b = 35\)[/tex]
The elimination method involves adding the two equations to eliminate one of the variables. Let's add these equations together:
[tex]\[
(5a + 5b) + (-5a + 5b) = 25 + 35
\][/tex]
Simplifying this, we see that the [tex]\(5a\)[/tex] and [tex]\(-5a\)[/tex] terms cancel each other out:
[tex]\[
0a + 10b = 60
\][/tex]
This simplifies to:
[tex]\[
10b = 60
\][/tex]
So, the resulting equation when elimination is used is [tex]\(10b = 60\)[/tex].