High School

When the argon is released from the canister, it expands to fill the wine bottle. How many 750.0 mL wine bottles can be purged with the argon in the canister at a pressure of 1.25 bar and a temperature of 307 K?

Answer :

Final answer:

Approximately 25 750.0 ml wine bottles can be purged with the argon in the canister.

Explanation:

According to the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature. By rearranging the equation, we can solve for the volume: V = (nRT) / P. Using the given values of pressure, temperature, and the volume of the wine bottle, we can calculate the number of wine bottles that can be purged:

V = (nRT) / P = (1 mol * 0.0821 L·atm/(mol·K) * 307 K) / 1.25 atm = 19.0336 L

Since each wine bottle has a volume of 0.75 L, we can divide the total volume by the volume of each wine bottle to find the number of wine bottles: 19.0336 L / 0.75 L = 25.3781 bottles. Therefore, approximately 25 750.0 ml wine bottles can be purged with the argon in the canister.

Learn more about Ideal Gas Law here:

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