Answer :
When K2Cr2O7 is cooled from 80oC to 20oC, 111.1 g/L of K2Cr2O7 will precipitate out of the solution.
The amount of solute that will precipitate out of a solution of K2Cr2O7 when it is cooled from 80oC to 20oC depends on the solubility of the compound at those temperatures. K2Cr2O7 is more soluble in hot water than in cold water, which means that as the temperature decreases, the solubility of the compound also decreases.
To determine the amount of solute that will precipitate out of the solution, we need to compare the solubility of K2Cr2O7 at 80oC and 20oC. According to the solubility data, the solubility of K2Cr2O7 in water at 80oC is 121 g/L, while the solubility at 20oC is 9.9 g/L.
Assuming that the original solution contained 121 g/L of K2Cr2O7, when the solution is cooled to 20oC, the amount of solute that will precipitate out can be calculated using the following equation:
Amount of solute precipitated = initial solute concentration - solute concentration at lower temperature
Amount of solute precipitated = 121 g/L - 9.9 g/L
Amount of solute precipitated = 111.1 g/L
Therefore, if the original solution contained 121 g/L of K2Cr2O7, when it is cooled from 80oC to 20oC, approximately 111.1 g/L of K2Cr2O7 will precipitate out of the solution. This is the maximum amount of solute that can precipitate out, assuming that the solution was saturated with K2Cr2O7 at 80oC.
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