Answer :
To solve the problem of determining which multiples of 3 and 6 the numbers 102, 108, 114, and 120 are, let's consider what it means for a number to be a multiple of another number.
1. Multiple of 3: A number is a multiple of 3 if it can be exactly divided by 3 (meaning there is no remainder).
2. Multiple of 6: Similarly, a number is a multiple of 6 if it can be divided by 6 without leaving a remainder.
Now, let's check each number to see if it satisfies these conditions:
- 102:
- Divide by 3: 102 ÷ 3 = 34 (no remainder), so 102 is a multiple of 3.
- Divide by 6: 102 ÷ 6 = 17 (no remainder), so 102 is also a multiple of 6.
- 108:
- Divide by 3: 108 ÷ 3 = 36 (no remainder), so 108 is a multiple of 3.
- Divide by 6: 108 ÷ 6 = 18 (no remainder), so 108 is a multiple of 6.
- 114:
- Divide by 3: 114 ÷ 3 = 38 (no remainder), so 114 is a multiple of 3.
- Divide by 6: 114 ÷ 6 = 19 (no remainder), so 114 is a multiple of 6.
- 120:
- Divide by 3: 120 ÷ 3 = 40 (no remainder), so 120 is a multiple of 3.
- Divide by 6: 120 ÷ 6 = 20 (no remainder), so 120 is a multiple of 6.
After checking each number, we can confirm that all four numbers (102, 108, 114, and 120) are multiples of both 3 and 6.
1. Multiple of 3: A number is a multiple of 3 if it can be exactly divided by 3 (meaning there is no remainder).
2. Multiple of 6: Similarly, a number is a multiple of 6 if it can be divided by 6 without leaving a remainder.
Now, let's check each number to see if it satisfies these conditions:
- 102:
- Divide by 3: 102 ÷ 3 = 34 (no remainder), so 102 is a multiple of 3.
- Divide by 6: 102 ÷ 6 = 17 (no remainder), so 102 is also a multiple of 6.
- 108:
- Divide by 3: 108 ÷ 3 = 36 (no remainder), so 108 is a multiple of 3.
- Divide by 6: 108 ÷ 6 = 18 (no remainder), so 108 is a multiple of 6.
- 114:
- Divide by 3: 114 ÷ 3 = 38 (no remainder), so 114 is a multiple of 3.
- Divide by 6: 114 ÷ 6 = 19 (no remainder), so 114 is a multiple of 6.
- 120:
- Divide by 3: 120 ÷ 3 = 40 (no remainder), so 120 is a multiple of 3.
- Divide by 6: 120 ÷ 6 = 20 (no remainder), so 120 is a multiple of 6.
After checking each number, we can confirm that all four numbers (102, 108, 114, and 120) are multiples of both 3 and 6.
