High School

When 13.99 mL of HCl of unknown concentration (but less than that of the base) is reacted with 13.00 mL of 2.14 M NaOH, 1.55 kJ of heat is released. What is the molarity of the HCl solution?

Answer :

When the 13.99 mL of the HCl of unknown concentration are with the 13 mL of the 2.14 M NaOH, The molarity of HCl is 1.98 M

The balance reaction is as follows :

NaOH + HCl --> NaCl + H₂O

The concentration, M1 = ?

The volume V1 = 13.99 mL

The concentration , M2 = 2.14 M

The volume , V2 = 13 mL

The expression is given as :

M1 V1 = M2 V2

M1 = M2 V2 / V1

M1 = ( 2.14 × 13 ) / 13.99

M1 = 1.98 M

Thus, the molarity of the HCl is 1.98 M.

To learn more about concentration here

https://brainly.com/question/26403608

#SPJ4