High School

When 0.5000 grams of an unknown hydrocarbon; C,H; is completely combusted with excess Oxygen 037 gas and produced at 98.3 "C and 0OO atm What is the empirical formula of the hydrocarbon? (R 0.08206 atm/mol-K) CHz C,H; CsHa CH,

Answer :

If the moles of carbon are 2 and the moles of hydrogen are 6, the empirical formula would be C2H6.

To determine the empirical formula of the hydrocarbon, we need to calculate the moles of carbon and hydrogen in the given sample.

First, let's calculate the moles of carbon (C) and hydrogen (H) separately.

Molar mass of carbon (C) = 12.01 g/mol

The molar mass of hydrogen (H) = 1.008 g/mol

Mass of carbon (C) = 0.5000 g

Mass of hydrogen (H) = To be determined

Using the ideal gas law equation, we can calculate the moles of hydrogen (H):

PV = nRT

Rearranging the equation:

n = PV / RT

n = (0.08206 atm/mol-K) * (98.3 + 273) K / 0.0 atm

Now, we can substitute the given values into the equation and calculate the moles of hydrogen:

n = (0.08206 * 371.3) / 0.0

Next, we need to convert the moles of carbon and hydrogen to the simplest whole-number ratio by dividing by the smallest number of moles.

Finally, we can write the empirical formula using the obtained ratio of carbon and hydrogen.

If the moles of carbon are 2 and the moles of hydrogen are 6, the empirical formula would be C2H6.

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