Answer :
Final answer:
Using Charles' Law, which states that the volume of a gas is directly proportional to its absolute temperature (assuming constant pressure), we find that the initial volume before the heating is approximately 839 mL.
Explanation:
When dealing with changes in volume and temperature of a gas, Charles' Law is often applicable. According to Charles' Law, the volume of a gas is directly proportional to its absolute temperature (in Kelvin), assuming the pressure is held constant.
To find the initial volume of the sample of carbon monoxide, you need to convert the temperatures from Celsius to Kelvin by adding 273.15. This gives T1 = 332.15 K (59.0 °C) and T2 = 391.15 K (118 °C).
According to Charles' law, (V1 / T1) = (V2 / T2). We need to solve for V1, so rearranging gives us V1 = (V2 * T1) / T2. Substituting the known values, we get V1 = (988 mL * 332.15 K) / 391.15 K = 837.92 mL.
Therefore, the initial volume of the sample of carbon monoxide was approximately 839 mL.
Learn more about Charles' Law here:
https://brainly.com/question/16927784
#SPJ11
