Middle School

Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ What volume does 0.87 mol of [tex]$H_2O(g)$[/tex] occupy at 36.2°C and 1.25 atm?

A. 2.06 L
B. 17.6 L
C. 37.1 L
D. 317 L

Answer :

Answer:

The answer is 17.66 L of volume occupy by water

Explanation:

According to ideal gas equation, the volume is calculated

PV= nRT

where V = volume

P = Pressure =.

n = number of moles,

T = temperature

Where R = 0.08206 L atm mol-1K-1 is constant

Convert the temperature value from degree centigrade to kelvin 1 °C = 273.15 K

By putting the values in the above equation as we have to find the volume so by adjusting

V= nRT/ P n= 0.87 mol P= 1.25 atm T= 36.2 °C= 309.35 K



V= (0.87mol) x (0.08206 L atm mol-1K-1 )x (309.3 K)/ 1.25 atm

V= 22.08 L atm /1.25 atm

Volume = 17.66 L

Other Questions