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------------------------------------------------ What is the velocity of the car, in meters per second, just after it hits a 145-kg deer initially running at 13 m/s in the same direction

To find the velocity of the car just after it hits the deer, we can use the principle of conservation of momentum. The equation for momentum is given by:

momentum = mass * velocity

Since there are no external forces acting on the car-deer system, the total momentum before the collision is equal to the total momentum after the collision.

Let's denote the velocity of the car just after the collision as Vc and the velocity of the deer just after the collision as Vd. The mass of the car is not given, so we'll use "m" to represent it.

Before the collision:
Momentum of car = mass of car * velocity of car = m * 0 (since the car is initially at rest)
Momentum of deer = mass of deer * velocity of deer = 145 kg * 13 m/s

After the collision:
Momentum of car = mass of car * velocity of car = m * Vc
Momentum of deer = mass of deer * velocity of deer = 145 kg * Vd

Using the conservation of momentum, we can set up the equation:

m * 0 + 145 kg * 13 m/s = m * Vc + 145 kg * Vd

Since the car hits the deer and they move together in the same direction, their velocities will be the same after the collision. Therefore, Vc = Vd.

Simplifying the equation:

0 + 1885 kg m/s = m * Vc + 145 kg * Vc
1885 kg m/s = (m + 145 kg) * Vc

Now we can solve for Vc:

Vc = 1885 kg m/s / (m + 145 kg)

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