High School

What is the solution of \(\log_2 x - 3125 = 3\)?

A. \(x = \frac{1}{3}\)

B. \(x = 1\)

C. \(x = \frac{7}{3}\)

D. \(x = 4\)

Answer :

The correct solution is x = 4, option D.

The solution of the equation log2x - 3125 = 3 can be found by isolating the term with the logarithm. First, let's assume the typos are actually meaning to state log(2x) = 3. To solve for x, we would use the property that if [tex]log_b[/tex](a) = c, then a = bc, where b is the base of the logarithm, a is the argument, and c is the log value.

Applying this property to the original equation, we would rewrite it as:

2x = 23

Since 23 is equal to 8:

2x = 8

Now we can divide both sides by 2 to solve for x:

x = 4

Therefore, the solution of the given logarithmic equation is x = 4, which corresponds to option d).

We have been asked to find the solution of

[tex] {Log_{(2x-3)}}^{125}=3\\
\\
\text{we can re-write after Removing logarithm as below}\\
\\
(2x-3)^3=125\\
\\
(2x-3)^3=5^3\\
\\
\text{Now take cubed root on both the sides we get}\\
\\
2x-3=5\\
\\
\text{Add 3 on both the sides we get}\\
\\
2x=8\\
\\
\text{Divide both the sides by 2 we get}\\
\\
x=4
[/tex]